Question

Two cubes each of side 8 cm are placed together. Find the surface area of the cuboid thus formed​

Answer 1

Dimensions of resulting cuboid arelength = (8 + 8 ) cm = 16cm

breadth = 8 cm

height = 8 cm

so,

Surface area of cuboid = 2 (lb + bh + hl) = 2 (16*8 + 8*8 + 8*16) = 2 (128 + 64 + 128) 

= 2* 320= 640

Hence surface area of resulting cuboid is 640 cm2​.

Answer 2

Step-by-step explanation:

$dimensions \: of \: resulting \: cuboid \\ length = 8 + 8 = 16 \\ breadth \: and \: height \: will \: remain \\ same \: = 8cm$

$surface \: area \: of \: cuboid \: \\ = 2(lb + bh + hl) \\ = 2(16 \times 8 + 8 \times 8 + 8 \times 16) \\ = 2(128 + 64 + 128) \\ = 2 \times 320 \\ = 640 \: {cm}^{2}$

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