two cubes each of the volume 729 cm are jointed end to end find the surface area of resulting cuboid
Nitin2311:
Ans is 810 sq cm
Answers
Answered by
8
I hope this will be helpful please make me brainliest it will help me
Attachments:
729 is the cube of 9
Answered by
30
volume of cube = side³
729=side³
9³= side³
9=side
so now the length of cuboid formed=9+9=18
breadth of cuboid=9
height of cuboid=9
so TSA=2(lb+bh+lh)
TSA=2(18*9+9*9+9*18)
TSA=2(162+81+162)
TSA=2(405)
TSA=810 cm²
729=side³
9³= side³
9=side
so now the length of cuboid formed=9+9=18
breadth of cuboid=9
height of cuboid=9
so TSA=2(lb+bh+lh)
TSA=2(18*9+9*9+9*18)
TSA=2(162+81+162)
TSA=2(405)
TSA=810 cm²
Similar questions