Two cubes each of volume 27^3 are joined end to end to from a solid. Find the surface area of the resulting cuboid.v
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each cube volume is 27 ^3
a^3=27^3
a=27
side of each cube is 27
h=27
b=27
l=27+27=54
surface area of cuboid is 2(lb+bh+hl)
7290square units
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Answer:
step by step :
if volume of a cube = a^3=27^3
therefore, a=27
the resultant cuboid of -
length=27+27=54unit
breadth=27 unit
height = 27unit
hence,
Total surface area = 2(lb+bh+hl)
= 2(54×27+27×27+54×27)
=2(1458+729+1458)
=2(3645)
=7290 unit^2
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