Question

two cubes each of volume 27 cm^3 ae joined end to end. find the surface area of the resulting cuboid. answer too..

Answer 1

side of cube =3cm
surface area of cuboid =2(lb+bh+hl)
l=3+3=6cm
b=3cm
h=3cm
=2(6*3+3*3+3*6)
=2(18+9+18)
=2*45
=90cm^2

Answer 2

Answer:

90 cm²

Step-by-step explanation:

Given that two cubes each of volume 27 cm³ are joined end to end to form a cuboid.

We know that, volume of cube = a³

where a = side of cube

So, a³ = 27 cm³

→ a = ∛27

→ a = 3 cm

Now the sides of cubes is 3 cm. Since they are joined end to end, their total length of cuboid formed = 3 + 3 = 6 cm

Height and breadth will remain the same. Hence, total surface area of cuboid = 2(lb + bh + lh)

→ 2(6 × 3 + 3 × 3 + 6 × 3)

→ 2(18 + 9 + 18)

→ 2(45)

→ 90 cm²