two cubes each of volume 64 are joined end to end .
find the total surface area of the resulting cuboid .
Answers
Answered by
0
TSA = 2(lb + bh + hl)
= 2(8×4 + 4×4 + 4×8)
= 2(32 + 16 +32)
= 2 × 80
= 160 sq units
Answered by
39
The Volume (V) of each cube is = 64 cm^3
This implies that a^3 = 64 cm^3
∴ The side of the cube, i.e. a = 4 cm
Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.
So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)
Now, by putting the values, we get,
= 2(8×4 + 4×4 + 4×8) cm^2
= (2 × 80) cm^2
Hence, TSA of the cuboid = 160 cm^2
Hope it's Helpful.....:)
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