Two cubes each of volume 64 cm^3 are joining face to face. what is the surface area of resulting cuboid ?
Answers
Answer:
160cm²
Step-by-step explanation:
Using the formula for the surface area of a cuboid = 2(lb + bh + lh), where l, b, and h are length, breadth, and height respectively.
Let the length of the edge of each cube be 'a'
Therefore, volume of the cube = a3
Volume of the cube, a3 = 64 cm3
a3 = 64 cm3
a = ∛(64 cm3)
a = 4 cm
Therefore,
Length of the resulting cuboid, l = a = 4 cm
Breadth of the resulting cuboid, b = a = 4 cm
Height of the resulting cuboid, h = 2a = 2 × 4 cm = 8 cm
Surface area of the resulting cuboid = 2 (lb + bh + lh)
= 2 (4 cm × 4 cm + 4 cm × 8 cm + 4 cm × 8 cm)
= 2 (16 cm2 + 32 cm2 + 32 cm2)
= 2 × 80 cm2
= 160 cm2
Thus, the surface area of the resulting cuboid is 160 cm2.
I HOPE THIS WILL HELP YOU
Answer:
volume of cube 64cm³
Side of cube ³√64=4cm
Surface area = 2(lb+hl+bh)
=2(4(4)+4(8)+8(4))
=2(16+32+32)
=2(80)=160cm²