two cubes each of volume 64 CM are joined end to end find the surface area of the resulting cuboid?
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S. Area of d cuboid is 160cm2
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Given:
- The Volume (V) of each cube is = 64 cm³.
This implies that a³ = 64 cm³
Therefore, a = 4 cm
Now,
The side of the cube = a = 4 cm
Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.
So, the surface area of the cuboid = 2(lb + bh + lh)
= 2(8×4 + 4×4 + 4×8) cm²
= 2(32 + 16 + 32) cm²
= (2 × 80) cm²
= 160 cm²
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