Question

two cubes each of volume 64 cm cube are joined end to end together find the surface area of the resulting cuboid​

Answer 1

Answer:

Given, volume of each cube is 64 cm³

⇒s³=64

⇒s=∛64

⇒s=4 cm.

When two cubes are joined , 

the length of the resulting cuboid(l) = side + side = 4+4 = 8 cm

its breadth(b) = side = 4cm

And its height(h) = side = 4cm

Total surface area of a cuboid = 2(lb+bh+hl)

⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]

⇒TSA=2(32+16+32)

⇒TSA = 2(80)

⇒TSA = 160 cm²

∴ The surface area of the resulting cuboid is 160 cm².

Answer 2

Answer: 160cm².

Step by step explanation:

Given,

Volume of both cubes = 64cm³

Volume of one cube =a^3

⇒ 64 = a³

⇒ (4) = a³

⇒ a=4

We know that, when two cubes are joined they form cuboid:

Length of cuboid=4+4= 8cm

Breadth of cuboid= 4cm

Height of cuboid= 4cm

Surface area of cuboid = 2(lb+bh+lh)

2(8×4+4×4+4×8)

= 2(32+16+32)

= 2(80)

= 160cm²

Therefore, Surface area of Cuboid is 160 cm².