Question

two cubes each of volume 64 cm cube are joined end to end together find find the surface area of the resulting cuboid ​

Answer 1

Answer:

164 cm

Step-by-step explanation:

side of a cube=

$\sqrt[3]{volume}$

=

$\sqrt[3]{64} = 4cm$

surface area of a cube is

$6 \times {side}^{2}$

area of cube 1 =

$6 \times {4}^{2} = 96$

on joining the two such cubes the area of the cuboid such formed will be

$(2 \times 96) - 2(area \: of \: one \: face)$

$(196) - 2( {4}^{2} )$

196-32

164 cm

Answer 2

Answer: 160cm².

Step by step explanation:

Given,

Volume of both cubes = 64cm³

Volume of one cube =a³

⇒ 64 = a³

⇒ (4) = a³

⇒ a=4

We know that, when two cubes are joined they form cuboid:

Length of cuboid=4+4= 8cm

Breadth of cuboid= 4cm

Height of cuboid= 4cm

Surface area of cuboid = 2(lb+bh+lh)

2(8×4+4×4+4×8)

= 2(32+16+32)

= 2(80)

= 160cm²

Therefore, Surface area of Cuboid is 160 cm².