two cubes each of volume 64 cm cube are joined end to end find the surface area of the resulting cuboid.
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Answered by
1
explanation:
SOLUTION
Volume of the cube = a³
Therefore,
a³ = 64
⇒ a³= (4)³
⇒ a = 4
Each side of the cube = 4 cm
Then,
length of the cuboid ⇒ (2 × 4)
Breadth of the cuboid = 4 cm
Height of the cuboid = 4 cm
Total surface area of the cuboid = 2(lb+bh+lh)
=2[(8 × 4)+(4 × 4)+(8 × 4)]cm²
=(2 × 80) cm²
= 160 cm²
Answered by
0
Answer:
we have to find their l , b , h
if it is cube it means all edges are same
so let the the edge x
x^3=64
x=3_/64
x=4cm
now we will connect them with breadth
now 2×(lb+bh+hl)
2×(4×8+8×4+4×4)
2×(32+32+16)
2x(80)
160cm
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