Two cubes each of volume 64 cm
o each of volume 64 cm3 are joined end to end to form a cuboid. Find the total
are joined end t
surface area of the cuboid.
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The Volume (V) of each cube is = 64 cm^3
This implies that a3 = 64 cm^3
∴ The side of the cube, i.e. a = 4 cm
Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.
So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)
Now, by putting the values, we get,
= 2(8×4 + 4×4 + 4×8) cm^2
= (2 × 80) cm√2
Hence, TSA of the cuboid = 160 cm^2
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