Two cubes each of volume 64 CM square are joined end to end together find the surface area of resulting cuboid
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Answer:
given: v=64
v of cube= s^3 [side cube]
64=s^3
s=4 [hence side of cube=4]
height of cuboid= 4
breadth of cuboid= 4
length of cuboid= twice side of cube= 8
hence, surface area of cuboid= lb+lh+bh
= 8(4) + 8(4) + 4(4)
= 32+ 32+ 16 = 80cm^2
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