Two cubes each of volume 64 cm3 are joined end to end. Find the surface area and volume of the resulting cuboid.
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Answered by
14
Given,
The Volume (V) of each cube is = 64 cm3
This implies that a3 = 64 cm3
∴ a = 4 cm
Now, the side of the cube = a = 4 cm
Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.
So, the surface area of the cuboid = 2(lb+bh+lh)
= 2(8×4+4×4+4×8) cm2
= 2(32+16+32) cm2
= (2×80) cm2 = 160 cm2
Answered by
7
Given,
The Volume (V) of each cube is = 64 cm3
This implies that a3 = 64 cm3
∴ a = 4 cm
Now, the side of the cube = a = 4 cm
Also, the length and breadth of the resulting cuboid will be 4 cm each. While its height will be 8 cm.
So, the surface area of the cuboid = 2(lb+bh+lh)
= 2(8×4+4×4+4×8) cm2
= 2(32+16+32) cm2
= (2×80) cm2 = 160 cm2
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