Two cubes each of volume 64 cm3 cube are joined end to end together. find the total surface area of the resulting cuboid?
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Answered by
10
Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².
Answered by
32
The Volume (V) of each cube is = 64 cm^3
This implies that a3 = 64 cm^3
∴ The side of the cube, i.e. a = 4 cm
Also, the breadth and length of the resulting cuboid will be 4 cm each while its height will be 8 cm.
So, the surface area of the cuboid (TSA) = 2(lb + bh + lh)
Now, by putting the values, we get,
= 2(8×4 + 4×4 + 4×8) cm^2
= (2 × 80) cm√2
Hence, TSA of the cuboid = 160 cm^2
Hope it's Helpful.....:)
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