Two cubes each of volume 64 cubic cm are joined end to end. Find the surface area and volume of the resulting cuboid
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Volume of small cube=64 cm^3
So,Edge of each cube=3√(64)=4cm
So,Edge of connected cubes=4×3=12cm
So,Volume of new cube=21^3=9261 cm^3
And,TSA=6a^2=6×12×12=864cm^2
So,Edge of each cube=3√(64)=4cm
So,Edge of connected cubes=4×3=12cm
So,Volume of new cube=21^3=9261 cm^3
And,TSA=6a^2=6×12×12=864cm^2
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Answer: 160cm².
Step by step explanation:
Given,
Volume of both cubes = 64cm³
Volume of one cube =a³
⇒ 64 = a³
⇒ (4) = a³
⇒ a=4
We know that, when two cubes are joined they form cuboid:
Length of cuboid=4+4= 8cm
Breadth of cuboid= 4cm
Height of cuboid= 4cm
Surface area of cuboid = 2(lb+bh+lh)
2(8×4+4×4+4×8)
= 2(32+16+32)
= 2(80)
= 160cm²
Therefore, Surface area of Cuboid is 160 cm².
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