two cubes each of volume 64cm³ are joined end to end. find the surface area of resulting cuboid?
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Answered by
7
Answer:
volume of cube=a^3
cubic root of 64=a
a=4cm
new dimensions of the two cubes joined will become a cuboid of dimension 4×8×4
surface area = 2 (lb+bh+hl)
= 2 (4×8+8×4+4×4)
= 2 (32+32+16)
= 2 (80)
= 160 sq. cm
Answered by
2
Answer:
l=8cm
B=4cm
h=4cm
Surface Area of cuboid =2(LB+BH+HL)
=2(8×4+4×4+4×8)
=2(32+16+32)
=2×80
Surface Area of cuboid =160cm²
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