Question

two cubes each of volume 64cmcube are joined end to end. find the surface area of resulting cube​

Answer 1

Answer:

Answer:

∴ The surface area of the resulting cuboid is 160 cm².

Step-by-step explanation:

Given, volume of each cube is 64 cm³

⇒s³=64

⇒s=∛64

⇒s=4 cm.

When two cubes are joined , 

the length of the resulting cuboid(l) = side + side = 4+4 = 8 cm

its breadth(b) = side = 4cm

And its height(h) = side = 4cm

Total surface area of a cuboid = 2(lb+bh+hl)

⇒TSA=2[(8)(4)+(4)(4)+(4)(8)]

⇒TSA=2(32+16+32)

⇒TSA = 2(80)

⇒TSA = 160 cm²

∴ The surface area of the resulting cuboid is 160 cm².

Answer 2

given the volume of the two cubes is 64cm³ each

formula for the volume of a cube is side × side × side or side³

therefore side³ = 64cm³

➡ side = ³√64

➡ side = ³√(4 × 4 × 4)

➡ side = 4cm

now ATQ, both the cubes are joined end to end.

so it became a cuboid now with

• length = 4 + 4 = 8cm

• breadth = 4cm

• height = 4cm

formula to find the surface area of a cuboid is 2(lb + bh + lh)

hence, it's surface area = 2(8 × 4 + 4 × 4 + 8 × 4)

= 2(32 + 16 + 32)

= 2 × 80

= 160cm² FINAL ANSWER