two cubes each of volume 729 cm cube are joined end to end find the surface area of resulting cuboid
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csa of cube=4a2
tsa of cube=csa cube 1+csa of cube 2
vol=a3
729=a3
9=a
csa of cube 1=4(9)2
csa=324
therefore 324+324=648 is the tsa of the new formed object
tsa of cube=csa cube 1+csa of cube 2
vol=a3
729=a3
9=a
csa of cube 1=4(9)2
csa=324
therefore 324+324=648 is the tsa of the new formed object
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