two cubes each of volume 74cm³ are joined end to end . find the surface area of resulting cuboids
Answers
Answer:
176.3 m²
Explanation:
to find side of cube :-
volume of cube = side³
74 = side³
∛ 74 = ∛side³
side = ∛ 74;
to find dimension of resulting cuboid :-
length of cuboid = ∛ 74 + ∛ 74
= 2∛ 74
width of cuboid = ∛ 74
height of cuboid = ∛ 74
to find surface area of cuboid :-
surface area of cuboid = 2(lb + bh + lh)
= 2(2∛ 74 × ∛ 74 + ∛ 74 × ∛ 74 + 2∛ 74 ×∛ 74)
= 2(2∛ 74*74 + ∛ 74*74 + 2∛ 74*74)
= 2(2∛5476 + ∛5476 + 2∛5476)
= 2(5∛5426)
= 10∛5476
= 10 × 17.63 (approx)
= 176.3 m²
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