Question

Two cubes each of volume 8cm 3 are joined end to end to form a solid. Find the surfaces areas of the cuboid so formed

Answer 1

$\underline{\mathfrak{\huge{The\:Question\:asked:}}}$

Two cubes each of volume $\sf{8\:cm^{3}}$ are joined end to end to form a solid. Find the surface areas of the cuboid so formed.

$\underline{\mathfrak{\huge{Here's \:Your\:answer:}}}$

We're Given that the volume of each cube is $\tt{8\:cm^{3}}$.

Side of the cube = $\tt{\sqrt{8}}$ cm

Side of the cube = $\tt{2\:cm}$

Thus, if we join the cubes end to end, we'll get a cuboid which will be:

Of Length = 2 + 2 + 2 cm = 8 cm

Of Breadth = 2 cm

Of Height = 2 cm

The total Surface Area of the cuboid = 2 ( lb + bh + lh )

The total Surface Area of the cuboid = 2 ( 8 × 2 + 2 × 2 + 8 × 2 )

The total Surface Area of the cuboid = 2 ( 16 + 4 + 16 )

The total Surface Area of the cuboid = 2 ( 36 )

The total Surface Area of the cuboid = $\boxed{\tt{72\:cm^{2}}}$