two cubes each of volumes 64 cm cube are joined end to end. Find the surface areas of resulting cuboid.
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Answered by
20
Volume of cube is given = 64 cm^3
So, Side = 3√64 = 4 cm.
Now, By joining two cubes,
New dimensions = 8cm, 4cm,4cm.
So, Surface of resulting cuboid = 2(lb+bh+lh) = 2(32+16+32) = 160 cm^2.
So, Side = 3√64 = 4 cm.
Now, By joining two cubes,
New dimensions = 8cm, 4cm,4cm.
So, Surface of resulting cuboid = 2(lb+bh+lh) = 2(32+16+32) = 160 cm^2.
Answered by
17
Volume of cube =(edge)^3=64
Edge=4cm.
Length of cuboid=4+4=8cm
Breadth=4cm
Hieght=4cm
Surface Area=2(lb+ bh+ hl)
Surface Area=2(32+16+32)
surface Area=2(80)
Surface Area of cuboid is 160cm^2.
Hope this will help u
Edge=4cm.
Length of cuboid=4+4=8cm
Breadth=4cm
Hieght=4cm
Surface Area=2(lb+ bh+ hl)
Surface Area=2(32+16+32)
surface Area=2(80)
Surface Area of cuboid is 160cm^2.
Hope this will help u
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