Question

Two cubes each volume 729cm3 are joined end to end Find the surface area of cuboid so formed

Answer 1

hey mate
we have volume of cube as 729
so take side as a
so a^3=729
a=9
when two cube are joined length will be 18 and breadth will be 9 and height will 9
so now it becomes a cuboid
so surface area of cuboid = 2(lh+bh+lb)=
2(405)=910
i hope u understood
plz mark it as brainliest!!++

Answer 2

Volume of a cube =729cm³

                         a³  = 729

                          a   =∛729

edge of the cube=9cm

length of the cuboid = 9+9=18

breadth of the cuboid= 9cm

height of the cuboid   =9cm

surface area of the cuboid= 2(lb +bh +hl)

                               ·               =2(18*9+9*9+9*18)

                                              =2(305)

                                              =610cm²

SURFACE AREA OF CUBOID =610cm²

HOPE IT HELPS!!!!