Two cubes, each with 8 cm edge are joined end to end. Find the surface area of resulting cuboid
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10
total surface area of cuboid
=surface area of two cubes-area of two sides
=
![2 \times 6 \times {8}^{2} - 2( {8)}^{2} \\ = 768 - 128 \\ = 640 2 \times 6 \times {8}^{2} - 2( {8)}^{2} \\ = 768 - 128 \\ = 640](https://tex.z-dn.net/?f=2+%5Ctimes+6+%5Ctimes++%7B8%7D%5E%7B2%7D++-+2%28+%7B8%29%7D%5E%7B2%7D++%5C%5C++%3D+768+-+128++%5C%5C++%3D+640)
=surface area of two cubes-area of two sides
=
Answered by
0
Answer:
640 cm²
Step-by-step explanation:
New length = 16
breadth = 8
height = 8
Surface area = 2 (lb + bh + lh)
= 2 (128 + 64 + 128)
= 2 * 320
= 640 cm²
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