Question

two cubes have their volumes 1 : 64. what is the ratio of their surface areas?​

Answer 1

Answer:

two cubes have their volumes 1 : 64.

this implies that

side³/side'³ = 1/64

side/side' = 1/4

the ratio of their surface areas

= 6side²/6side'²

= side²/side'²

= (1/4)²

= 1/16

the ratio of their surface areas is 1:16