two cubes have their volumes 1 : 64. what is the ratio of their surface areas?
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Answer:
two cubes have their volumes 1 : 64.
this implies that
side³/side'³ = 1/64
side/side' = 1/4
the ratio of their surface areas
= 6side²/6side'²
= side²/side'²
= (1/4)²
= 1/16
the ratio of their surface areas is 1:16
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