Question

two cubes have their volumes in th ratio 1:64 . find the ratio of of their surface areas

Answer 1

here is your answer........................

Answer 2

let volume of two cubes be V^3,x^3
ratio of volumes =1/64
V^3/X^3 =1/64

${(v \div x)}^{3} = 1 \div 64 \\ (v \div x) = \sqrt[3]{1 \div 64} \\( v \div x) = 1 \div 4$
ratio of surface areas =6v^2/6x^2
$(6 {v}^{2} ) \div( 6 {x}^{2} ) \\ = {v}^{2} \div {x}^{2} \\ = (\frac{v}{x} )^{2} \\ = ( \frac{1}{4} )^{2} \\ = \frac{1}{16}$
so,ratio of surface areas is 1/16.