Question

Two cubes have their volumes in the ratio 1: 27 then the ratio of their
surface areas is what?​

Answer 1

Answer:

we know that the Volume of a cube is a cube of its side and the Surface area is six times its square of side.

Let a

1

,a

2

be sides of two cubes.

⇒V=a

3

and Surface area =6a

2

Given, V

1

:V

2

=1:27

⇒V

1

:V

2

=a

1

3

:a

2

3

⇒a

1

3

:a

2

3

=1:27

⇒a

1

:a

2

=1:3

⇒a

1

2

:a

2

2

=1:3

2

=1:9

Sa

1

:Sa

2

=6a

1

2

:6a

2

2

=a

1

2

:a

2

2

=1:9

Therefore, the ratio of surface areas is 1:9.

Step-by-step explanation:

please mark as brainlist.....

Answer 2

Answer:

$1:9$

Step-by-step explanation:

We know that:

The volume of cube is a cube of its side and the surface area is six times its square of side.

Let a₁, a₂ be side of two cubes

$→v=a³$ and surface area =6a²

Given,

$→v₁:v₂=1:27$

$→v₁:v₂=a³₁:a₂³$

$→a₁³:a³₂=1:27$

$→a₁:a₂=1:3$  

$→a²₁:a²₂=1:3²=1:9$

sa₁:sa₂=6a₁²:6a₂²=a₁²:a₂²=1:9[/tex]

Therefore,

The ratio of surface areas is 1:9