Question

two cubes of masses 3g and 6g and side of length 2cm and 3cm respectively are placed on a smooth table caluclate the pressure exerted on the ground​

Answer 1

Explanation:

P=\frac{mg}{a^2}+\frac{Mg}{b^2}\\P=\frac{(0.003)(9.8)}{0.02^2}+\frac{(0.006)(9.8)}{0.03^2}\\P=139\ PaP=

a

2

mg

+

b

2

Mg

P=

0.02

2

(0.003)(9.8)

+

0.03

2

(0.006)(9.8)

P=139 Pa

Here is your answer ....