Two cubes of volume 125 cm 3 are joined end to end to form a cuboid. The surface area of the resulting cuboid is
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Answered by
34
Volume of cube=125 cm³
Volume of cube= (side)³
125=(side)³
∛125=side
5 cm= side
When 2 cubes are joined,
Length of cuboid=5+5=10 cm
Breadth of cuboid=5 cm
Height of cuboid=5 cm
Surface area of cuboid= 2(lb+bh+hl)
" =2[(10x5)+(5x5)+(10x5)]
=2[50+25+50]
=2x125
250 cm²
Volume of cube= (side)³
125=(side)³
∛125=side
5 cm= side
When 2 cubes are joined,
Length of cuboid=5+5=10 cm
Breadth of cuboid=5 cm
Height of cuboid=5 cm
Surface area of cuboid= 2(lb+bh+hl)
" =2[(10x5)+(5x5)+(10x5)]
=2[50+25+50]
=2x125
250 cm²
shilpasinghal66:
surface area of cuboid is 250cm sq.
Answered by
8
let side of cube be a
a CUBE=125
a=5
TSA of cuboid=2(5 *a sq)
=10*25=250cmsq
a CUBE=125
a=5
TSA of cuboid=2(5 *a sq)
=10*25=250cmsq
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