Question

Two cubical dice are thrown simultaneously, the probability of getting sum of at most 9 is

a) 1/4 b) 1/6 c) 1/9 d) 30/36
​

Answer 1

Answer:

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Step-by-step explanation:

Throwing two dimensional no. of events =6

2

=36

Let A be the event of getting even no, and B be the event of getting sum 9.

Then

A={(2,2),(2,4),(2,6),(4,2),(4,4),(4,6),(6,2),(6,2),(6,4),(6,6)}

n(A)=9

P(A)=

n(5)

n(A)

=

36

9

=

4

1

B={(3,6),(4,5),(5,4),(6,3)}

n(B)=4

P(B)=

n(S)

n(B)

=

36

4

=

9

1

Since A and B are mutually exclusive,

P(A∪B)=P(A)+P(B)=

4

1

+

9

1

=

36

13

Answer 2

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