Two cubical dice are thrown
simultaneously, the probability of
getting total 7 is
1/4
1/6
1/9
1/36
Answers
Answered by
0
Answer:
1/36
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Answered by
0
Answer:
1/6 as
total outcomes=36
favourable outcomes=6{(1,6)(2,5)(3,4)(4,3)(5,2)(6,1)}
so, P(E)=6/36=1/6
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