two cubical dice are tossed find the probability of the following even divisible by 3 less than 7 not less than 7 ( or at least 7 or more than 6)
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Answer:
Step-by-step explanation:
Total number of ways in which 2 dice may be thrown.
n(S)=6×6=36
Event of getting a sum 7 on the uppermost faces
⇒n(E)={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)
n(E)=6
∴ The probability of getting a sum 7
P(A)=
n(S)
n(E)
=
36
6
=
6
1
The probability of obtaining a sum which is either greater or less than 7 will be complementary to the probability of getting the sum of exactly 7.
P(A
′
)=1−P(A)
=1−
6
1
=
6
5
.
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