two cubical dice having edge 2 cm are joined end to end. Find surface area of that solid so formed
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If we join two cubes with each other,the cuboid will be form having dimensions 4 , 2 , 2 respectively..
so the T.S.A. = 2 (LB + BH + LH)
T.S.A. = 2 ( 4×2 + 2×2 + 2×4)
T.S.A. = 2 (8 + 4 + 8)
T.S.A. = 2 (20)
T.S.A. = 40 cm^2
so the T.S.A. = 2 (LB + BH + LH)
T.S.A. = 2 ( 4×2 + 2×2 + 2×4)
T.S.A. = 2 (8 + 4 + 8)
T.S.A. = 2 (20)
T.S.A. = 40 cm^2
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the total surface area of the cubicle dice formed would be 40 cm²
with length of 4 cm and breadth of 2 cm height of 2 cm
with length of 4 cm and breadth of 2 cm height of 2 cm
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