Question

Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once . find the probability that the sum of the two numbers occurring on their top faces is mor than 7

Answer 1

Answer:

Step-by-step explanation is below in the captured image

Answer 2

The probability that  the sum of the two numbers occurring on their top faces is more than 7 is $\frac{5}{12}$

Step-by-step explanation:

Given : Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once.

To find : The probability that the sum of the two numbers occurring on their top faces is more than 7 ?

Solution :  

When two dice are thrown,

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)  

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)  

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)  

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)  

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)  

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)  

The favorable outcome is getting the sum of the two numbers occurring on their top faces is more than 7 i.e. {(2,6) ,(3,5) (3,6),(4,4), (4,5), (4,6),(5,3),(5,4), (5,5), (5,6),(6,2), (6,3), (6,4), (6,5), (6,6)}=15

Total number of outcome = 36

The probability is given by,

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total outcome}}$

$\text{Probability}=\frac{15}{36}$

$\text{Probability}=\frac{5}{12}$

The probability that  the sum of the two numbers occurring on their top faces is more than 7 is $\frac{5}{12}$

#Learn more  

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