Math, asked by Rayanahmed7890, 11 months ago

Two cubical dice whose faces are numbered 1 to 6 are rolled simultaneously once. find the probability that the sum of the numbers occuring in their top faces is more than 7.​

Answers

Answered by ANUJA1105
14

Answer:

S={(1,1);(1,2);(1,3);(1,4);(1,5),(1,6);(2,1);(2,2);(2,3);(2,4);(2,5);(2,6);(3,1);(3,2);(3,4);(3,5);(3,6);(4,1);(4,2);(4,3);(4,4);(4,5);(4,6);(5,1);(5,2);(5,3);(5,4);(5,5);(5,6);(6,1);(6,2);(6,3);(6,4);(6,4);(6,5);(6,6)}

n(S)= {36}

event A: to get number that it's sum is more than 7

(A)= {(2,6);(3,6);(4,6),(5,6);(6,6);(3,5);(4,4);(4,5);(5,3);(5,4);(5,5);(5,6);(6,2),(6,3),(6,4);(6,5);(6,6)}

n(A)= 17

p(A)= n(A)/n(S)= 17/36

hope this helps you

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