Two cubical die where faces are marked with digits 1 to 6 are thrown simultaneously. Find the probability that
the sum of the digits on the face that turn up is (1)8, and (II) 11
Answers
Step-by-step explanation:
What would you like to ask?
11th
Maths
Probability
Axiomatic Approach to Probability
If two cubical dice are thr...
MATHS
avatar
Asked on October 15, 2019 by
Niharika Sachdeva
If two cubical dice are thrown simultaneously, then find the probability of getting the sum of numbers 'more than 7' or 'less than 7'.
MEDIUM
Share
Study later
VIDEO EXPLANATION
ANSWER
Total number of ways in which 2 dice may be thrown.
n(S)=6×6=36
Event of getting a sum 7 on the uppermost faces
⇒n(E)={(1,6),(2,5),(3,4),(4,3),(5,2),(6,1)
n(E)=6
∴ The probability of getting a sum 7
P(A)=
n(S)
n(E)
=
36
6
=
6
1
The probability of obtaining a sum which is either greater or less than 7 will be complementary to the probability of getting the sum of exactly 7.
P(A
′
)=1−P(A)
=1−
6
1
=
6
5
.