Question

two customers are visiting a particular shop in the same week (Monday to Saturday) each is equally likely to visit the shop on any one day as on another. what is the probability that both will visit the shop
(1)the same day?
(2) different days?
(3)consecutive days?

Answer 1

Answer:

same day

Step-by-step explanation:

because if they are equally likely to visit the shop on the same day then they are both likely to visit the shop at the same time

Answer 2

Answer:

$(1)$ $\frac{1}{6}$

$(2)\frac{5}{36} \\\\(3)\frac{5}{6}$

Step-by-step explanation:

Total days are- Mon, Tue, Wed, Thur, Fri, Sat

i.e. 6.

Total possible outcomes =6*6=36

They are:

(Mon, Mon), (Mon, Tues) (Mon, Wed) .... (Mon, Sat)

(Tues, Mon), (Tues, Tues) (Tues, Wed) .... (Tues, Sat)

....

 (Sat, Mon), (Sat, Tues) (Sat, Wed) .... (Sat, Sat)

(1) Probability that they both will visit in the same day:

Total number of days that they will visit on the same day = 6

They are:

(Mon, Mon), (Tues, Tues), (Wed, Wed), (Thurs, Thurs), (Fri, Fri), (Sat, Sat)

Thus the probability of the situation is 6/36

=1/6

(2)Total number of days that can be consecutive = 5

They are:

(Mon, Tue), (Tue, Wed), (Wed, Thurs), (Thurs, Fri), (Fri, Sat)

So, the probability of the situation becomes 5/36

(3) probability of same days = 1/6

probability of different days= 1 - probability of same days

                                             = 1- 1/6

                                             =5/6