Question

Two customers Shyam and Ekta are visiting a particular shop in the same week (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on
(i) the same day? (ii) consecutive days? (iii) different days?

Answer 1

Answer:

Step-by-step explanation:

Total number of days from Tuesday to Saturday = 5

Therefore both of them can reach the shop in 5 ways.

Thus, the total number of outcomes = 5 × 5 = 25 = 25 ways.

The possible combination to reach the shop will be -

(Tuesday, Tuesday TT)(Wednesday, Wednesday WW)(Thursday, Thursday TH TH)(Friday, Friday FF) and (Saturday, Saturday SS) 

1) Probability of reaching the same day -

= 5/25 

= 1/5 

2) Probability of reaching on consecutive days -

They can reach on consecutive days in following 8 ways -

(Tuesday, Wednesday TW) ; (Wednesday, Tuesday WT) ; (Wednesday, Thursday WTH) ; (Thursday, Wednesday THW) ; (Thursday, Friday THF) ; (Friday, Thursday FTH) ; (Friday, Saturday FS) and (Saturday, Friday SF)

= 8/25

3) Probability of reaching on different days -

Since, the probability of reaching on same days = 1/5

Thus, the probability of reaching on different days = 1 - 1/5 

= 4/5

Answer 2

Answer:

Step-by-step explanation:

Step-by-step explanation:

Total number of days from Tuesday to Saturday = 5

Therefore both of them can reach the shop in 5 ways.

Thus, the total number of outcomes = 5 × 5 = 25 = 25 ways.

The possible combination to reach the shop will be -

(Tuesday, Tuesday TT)(Wednesday, Wednesday WW)(Thursday, Thursday TH TH)(Friday, Friday FF) and (Saturday, Saturday SS)

1) Probability of reaching the same day -

= 5/25

= 1/5

2) Probability of reaching on consecutive days -

They can reach on consecutive days in following 8 ways -

(Tuesday, Wednesday TW) ; (Wednesday, Tuesday WT) ; (Wednesday, Thursday WTH) ; (Thursday, Wednesday THW) ; (Thursday, Friday THF) ; (Friday, Thursday FTH) ; (Friday, Saturday FS) and (Saturday, Friday SF)

= 8/25

3) Probability of reaching on different days -

Since, the probability of reaching on same days = 1/5

Thus, the probability of reaching on different days = 1 - 1/5

= 4/5