two cycles were bought at same cost.one was sale at profit of 15% and another was sold at loss of 10%.if the difference in seeling prise is ₹200,find the cost of the cycles
Answers
Answered by
0
Step-by-step explanation:
Let c.p of one be x
The c.p of other be. y
S.p of first=x(120/100)=6x/5
S.p of other=y(80/100)=4y/5
Total c.p=x+y
Total s.p=(6x+4y)/5
6x/5=4y/5 (given)=3x=2y
Now c.p=x+3x/2=5x/2
S.p=(6x+6x)/5=12x/5
Loss=c.p-s.p=20 (given)
5x/2-12x/5=20
X/10=20
X=₹200
Similar questions