Question

Two cycles were bought at the same cost. One was sold at a profit of 15% and another was sold
at a loss of 10%. If the difference in selling price is 3200, find the cost of the cycles.
Ridhan loses 10% by selling an article for 3900. If he had sold the article for 31100, what is​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.

Answer 2

Let c.p of one be x

The c.p of other be. y

S.p of first=x(120/100)=6x/5

S.p of other=y(80/100)=4y/5

Total c.p=x+y

Total s.p=(6x+4y)/5

6x/5=4y/5 (given)=3x=2y

Now c.p=x+3x/2=5x/2

S.p=(6x+6x)/5=12x/5

Loss=c.p-s.p=20 (given)

5x/2-12x/5=20

X/10=20

X=₹200

Y=(3/2)200=₹300