Question

Two cycles were bought at the same cost. One was sold at a profit of 15% and another was sold at a loss of 10%. If the difference in selling price is ₹200,find the cost of the cycles.​

Answer 1

Answer:

Let the C P of the toy = Rs.1oo

If the gain is 12%, the first S P = 100 + 12

                                                     = Rs.112

If he had been sold Rs.33 more gain = 14 %

Therefore

second S P = 100 + 14

                     = Rs 114 .

Difference in second S P and first S P =114 - 112

                                                                   = Rs.2

If Rs,2 is the difference in S P , cost price = Rs. 100

If the difference in S P is Rs.33, cost price = 100/2*33

                                                                          = 50 x 33

                                                                            = Rs1650

Answer 2

Solutions :-

Let the Cost price of each cycle be x

Find the Selling price of a cycle at a profit of 15% :-

S.P = C.P + 15% of C.P
= x + 15% of x
= x + 0.15x
= 1.15x


Find the Selling price of other cycle at a loss of 10% :-

S.P = C.P - Loss % of C.P
= x - 10% of x
= x - 0.10x
= 0.90x


Given : The difference in selling price is ₹200

Difference in its selling price = 1.15x - 0.90x = 0.25x


According to the question,

0.25x = 200
=> x = 200/0.25 = 800


Hence,
Cost Price of each cycle = Rs 800
Cost Price of both cycles = Rs (800 × 2) = Rs 1600