Question

two cycles were bought at the same cost . one was sold ata profit of 15% and another was sold at a loss of 10% . if the difference in selling price is 200 , find the cost of the cycles.​

Answer 1

Answer ☞

$x = 800$

Step - by - step

Explanation ☞

Let the CP of 1st cycle be

$= x$

And , 2nd

$= x$

1st cycle SP

$= (\frac{115 \: x}{100} )$

And , 2nd

$= ( \frac{90 \: x}{100} )$

$= ( \frac{115 \: x}{100} ) - ( \frac{90 \: x}{100} ) = 200 \\ \\ x = 800$

So , the cost of the cycles are = 800

Hope it helps (*ω*)