Question

Two cyclist are moving on the road. One cyclist is moving with the speed of the 5 m/s towards the second cyclists and second cyclist is moving towards the fitst cyclists with the speed of the 8 m/s in a path of 500m. After how much time thay will meet together?

Best answer will be appreciated, Rated, also will be marked as Brainliest. Weong answer will be deleted on the spot.

Answer 1

Hi ,

Let first cyclist is A .

second cyclist is B .

distance of the path = d = 500m

speed of A = 5m/s

speed of B = 8m/s

Relative speed of cyclists ( they are moving

opposite direction ) = S = 5 + 8 = 13m/s

Time taken to meet each other = d/S

t = ( 500/13 ) sec

I hope this helps you.

: )

Answer 2

Hi,

Please see the attached file!



Thanks