Math, asked by ManojGhera3180, 1 year ago

Two cyclist start from same person one goes toward north at 12 km/h and other goes towards east 16 km/h .What tym will they take to be 10 km apart

Answers

Answered by sherafrazkhan123
0

Answer:

Step-by-step explanation:

Using pythagoras Theorem

distance covered toward north = 12/x

distance covered toward east= 16/x

(12/x)^2 + (16/x)^2 = 10^2

(144 + 256)/x^2 = 100

400 = 100x^2

x^2 = 4

x= 2, -2 ignore negative term as time can't be negative

so after 2 hours the distance between the two cyclists will be 10 km

Similar questions