Two cyclists make the same trip. The first one take 3.5 hours and the second ,with a speed that is 1km/h greater than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance covered in the trip.
Answers
Answer:
making √45≈±3⋅2.2=±6.6 . In actuality, ∣∣√5∣∣≈2.236 , and √45≈±6.708 , so it's not too bad of a guess
Question:-
Two cyclists make the same trip. The first one take 3.5 hours and the second ,with a speed that is 1km/h greater than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance covered in the trip.
Given:-
Two cyclists make the same trip.
Time Taken by first cyclist = 3.5 hrs
Time Taken by second cyclist = 3 hrs
To Find:-
speed of the two cyclists.
distance covered in the trip.
Solution:-
Let the speed of first cyclist be x
Time taken by the first cyclist = 3.5 hours
Distance Travelled by first cyclist
⇒speed × time
⇒ 3.5x
We are given that the second with a speed that that is 1 km/h greater than that of the first, takes 3 hours .
So,
The speed of the second cyclist = x + 1
Time Taken by second cyclist = 3 hours
Distance Travelled by second cyclist
⇒Speed × Time
⇒ 3(x + 1)
Since we are given that cyclist travelled the same time
So,
3.5x = 3(x + 1)
3.5x = 3x + 3
0.5 x = 3
x = 3/0.5
x = 6
Distance Travelled by the first cyclist
⇒ 3.5x = 3.5(6)
⇒ 21
Hence, The distance covered in the trip is 21km
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