Two cyclists make the same trip. The first one take 3.5 hours and the second ,with a speed that is 1km/h greater than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance covered in the trip.
Answers
Answer:
speed of 1st cycle is 6km/hr and second cycle is 7 km/hr
distance is 21 km
Step-by-step explanation:
Given,
Two cyclists make the same trip
so distance is same for both cyclists
First on take 3.5 hr with x km/hr
second one took 3 hrs with (x+1)km/hr
let s1 and t1 is speed of first cycle
s2 and t2 is speed of second cycle
we know speed=Distance/time
Distance=Speed*time
if distance is same
then
s1*t1=s2*t2
3.5*x=3*(x+1)
35/10*x=3x+3
35x=30x+30
5x=30
x=6 km/hr (speed of first cycle)
x+1=(6+1)
=7 km/hr (speed of second cycle)
Distance=7*3
=21
Question:-
- Two cyclists make the same trip. The first one take 3.5 hours and the second ,with a speed that is 1km/h greater than that of the first ,take 3 hours.find the speed of the two cyclists.also find the distance covered in the trip.
Given:-
- Two cyclists make the same trip.
- Time Taken by first cyclist = 3.5 hrs
- Time Taken by second cyclist = 3 hrs
To Find:-
- speed of the two cyclists.
- distance covered in the trip.
Solution:-
Let the speed of first cyclist be x
Time taken by the first cyclist = 3.5 hours
Distance Travelled by first cyclist
⇒speed × time
⇒ 3.5x
We are given that the second with a speed that that is 1 km/h greater than that of the first, takes 3 hours .
So,
The speed of the second cyclist = x + 1
Time Taken by second cyclist = 3 hours
Distance Travelled by second cyclist
⇒Speed × Time
⇒ 3(x + 1)
Since we are given that cyclist travelled the same time
So,
3.5x = 3(x + 1)
3.5x = 3x + 3
0.5 x = 3
x = 3/0.5
x = 6
Distance Travelled by the first cyclist
⇒ 3.5x = 3.5(6)
⇒ 21
Hence, The distance covered in the trip is 21km
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