Two cyclists make the same trip. The first one takes 3.5 hours and the second, with a
speed that is 1 km/h greater than that of the first, takes 3 hours. Find the speeds of the tw
cyclists. Also find the distance covered in the trip.
Spammers stay away!!!
Answers
Hope it helps you.
Sorry for the breakage of photo
Step-by-step explanation:
Given :-
Two cyclists make the same trip. The first one takes 3.5 hours and the second, with a
speed that is 1 km/h greater than that of the first, takes 3 hours.
To find :-
Find the speeds of the two cyclists. Also find the distance covered in the trip.?
Solution :-
Let the speed of the first cyclist be X km/hr
Then the speed of the second cyclist
= 1 km /hr greater than that of first cyclist
= (X+1) km/hr
Time taken by the first cyclist = 3.5 hours
We know that
Distance = Speed×Time
=> D = 3.5X km -----------(1)
Time taken by the second cyclist = 3 hours
=> Distance = 3×(X+1)
=> D = (3X+3) km/hr -------(2)
Given that
Two cyclists make the same trip
=> 3.5X = 3X+3
=> 3.5X-3X = 3
=> 0.5X = 3
=> (5/10)X = 3
=> X/2 = 3
=> X = 3×2
=> X = 6 km/hr
The speed of first cyclist = 6 km/hr
and
The speed of the second cyclist = 6+1 = 7 km/hr
Total distance = D = 3.5×6
=> D = 21.0 km
=> Distance = 21 km
Answer:-
The speed of first cyclist = 6 km/hr
The speed of the second cyclist = 7 km/hr
Total distance covered in the trip = 21 km
Used formulae:-
→ Distance = Speed×Time