two cyclists start from the same placed in opposite directions. One goes towards north at 18 kmph and the other goes towards south at 20 kmph. What time will they take to be 47.5 km apart
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distance of first cyclist=47.5
speed of first cyclist =18kmph
time of first cyclist =475÷18×10
time=2hours 35 min
distance of second cyclist =47.5
speed of second cyclist =20kmph
time =475÷20×10=4 hours
speed of first cyclist =18kmph
time of first cyclist =475÷18×10
time=2hours 35 min
distance of second cyclist =47.5
speed of second cyclist =20kmph
time =475÷20×10=4 hours
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