Question

Two cylinder of metal weight 1 kg and 7 kg the radius of the smaller sphere is 3 cm the two spheres are melted to form a single big sphere find the diameter of the big sphere

Answer 1

Answer:

Total weight of recasted sphere is 1kg+7kg=8kg

Radius of the small metal 'r'=3 cm.

Hence, density of the metal

1kg /4/3$\pi$r$^{3}$

3/4×$\pi$×27

=> 1/36 kg/cm$^{3}$

Let the radius of the recasted metal be 'R'

8= 1/36 kg/cm$^{3}$  ×4/3$\pi$r$^{3}$

=> R$^{3}$  =216

=> R=6 cm

Diameter of the big sphere = 2r

=> 2 ×6

=> Diameter of the big sphere = 12 cm

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@GauravSaxena01