Question

Two cylindercal vessels have their base radius as 16 cm and 8 cm if their height are 8 cm and 18 cm and 16 cm respectively then find the ratio of their volume​

Answer 1

CORRECT QUESTION

• Two cylindercal vessels have their base radius as 16 cm and 8 cm if their height are 18 cm and 16 cm respectively then find the ratio of their volume.

${\bold{\underline{\underline{Answer:}}}}$

${\bold{\therefore Volume_{1}:Volume_{2}=9:2}}$

${\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\underline \bold{Given : } \\ \implies Radius_{1} = 16 \: cm\\ \\ \implies Radius_{2} =8 \: cm \\ \\ \implies Height_{1} = 18 \:cm \\ \\ \implies Height_{2} =16 \: cm \\ \\ \underline \bold{To \: Find : } \\ \implies Volume_{1} : Volume _{2} = ?$

• According to given question :

$\bold{Using \: formula \: of \: Volume \: of \: cylinder :} \\ \implies Volume_{1} = \pi { r_{1} }^{2} h_{1}\\ \\ \implies Volume_{1} =\pi \times 16 \times 16 \times 18 \\ \\ \bold{ \implies Volume_{1} =4608\pi} \\ \\ \bold{For \: Volume_{2}} \\ \implies Volume_{2} =\pi { r_{2} }^{2} h_{2} \\ \\ \implies Volume_{2} =\pi \times 8 \times 8 \times 16 \\ \\ \bold{ \implies Volume_{2} =1024\pi} \\ \\ \bold{ For\: Ratio : } \\ \implies \frac{ Volume_{1}}{volume_{2} } = \frac{\cancel{4608}\times\cancel{\pi}}{\cancel{1024}\times\cancel{\pi}} \\ \\ \implies \frac{ Volume_{1}}{Volume_{2} } = \frac{9}{2} \\ \\ \bold{\implies Volume_{1} :Volume_{2} = 9 :2}$

Answer 2

Step-by-step explanation:

Hey mate

Refer to the attachment