Question

(two cylinderical vessels are filled with milk.the radius of one vessel is 15 CM and height is 40 CM. the radius of other vessels is 20cm and height 45 CM find the radius of another cylindrical vessel of height 30cm which may just contain the milk which is in the two given vessels.)

Answer 1

it means the volume of the two small vessels are equal to that of the big one
πR²=πr²+πr²
πR²=π(r²+r,²)
R²=r²+r,²
R²=15²+20²
R²=225+400=625=√625=25
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Answer 2

$\huge \underline \mathbb {SOLUTION:-}$

Given:

• Radius of 1st cylinder = 15cm
• Height of 1st cylinder = 40 cm

• Radius of 2nd cylinder = 20 cm
• Height of 2nd cylinder = 45 cm

• Also, height of new cylinder = 30 cm

ExPlanation:

Let the radius of new cylinder be r cm.

Sum of volumes of 1st and 2nd cylinder = volume of new cylinder

π × 152× 40 + π × 202× 45 = πr²× 30

⇒(225 × 40 + 400 × 45) = r² × 30

⇒ 9000 + 18000 = r² × 30

⇒27000 = r² × 30

⇒r² = 900

⇒r² = 302

⇒r = 30 cm

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